1 solutions

  • 1
    @ 2026-2-1 16:07:54

    #include <bits/stdc++.h> using namespace std;

    int main() { long long s, z; long long max1 = 0; long long min1 = 1000000000; cin >> s; for (int i = 0; i < s; i++) { cin >> z; max1 = max(max1, z); min1 = min(min1, z);

    }
    cout << max1 - min1 << endl;
    
    
    
    return 0;
    

    }

    • 1

    【深基4.习5】求极差 / 最大跨度值 / 最大值和最小值的差

    Information

    ID
    9811
    Time
    1000ms
    Memory
    125MiB
    Difficulty
    1
    Tags
    (None)
    # Submissions
    200
    Accepted
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