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#include <bits/stdc++.h>
using namespace std;

int a[30] = {0, 3, 6, 6, 2, 4, 7, 2, 5, 1, 3, 6, 1};

int b[30] = {0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};

int main() {
	int n;
	cin >> n;
	cout << "MON TUE WED THU FRI SAT SUN\n";
	int s = a[n];
	for (int i = 1; i <= a[n] * 4 - 2; i++)
		cout << " ";
	for (int i = 1; i <= b[n]; i++) {
		if (i == 1)
			cout << i << " ";
		else
			cout << setw(3) << i << " ";
		if (s % 7 == 0)
			cout << "\n";
		s++;
	}
	return 0;
}

这题我们先用日历查出买个月第一天是星期几、有几天，再把固定格式（MON TUE WED THU FRI SAT SUN）输出，接着输出第一天之前的空格最后输出每个日期，日期输出除了我那样，还可以cout<<(i<10?" "/三个空格/:" "/两个空格/)<<i<<" "/一个空格/;。