1 条题解
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1
#include <bits/stdc++.h> using namespace std;
int main() { int n, a[15]; double s = 0; cin >> n; for (int i = 1; i <= n; i++) { cin >> a[i]; s = s + a[i]; } double AVE = 1.0 * s / n; cout << "AVE=" << fixed << setprecision(1) << AVE << endl; for (int i = 1; i <= n; i++) { if (a[i] > AVE) { cout << i << ":" << a[i] << " "; } } return 0; }
- 1
信息
- ID
- 30146
- 时间
- 1000ms
- 内存
- 256MiB
- 难度
- 4
- 标签
- 递交数
- 116
- 已通过
- 55
- 上传者