壹look这题就是一题分支题因为直接cin两个变量太不美观了，所以用数组

#include <bits/stdc++.h>
using namespace std;
#define ll long long
ll a[5];

void ych(ll &x) {
	int f = 1;
	x = 0;
	char ch = getchar();
	while (ch < '0' || ch > '9') {
		if (ch == '-')
			f = -1;
		ch = getchar();
	}
	while (ch >= '0' && ch <= '9') {
		x = x * 10 + ch - '0';
		ch = getchar();
	}
	x *= f;
}
ll sum;

int main() {
	for (int i = 1; i <= 4; i++) {
		ych(a[i]);
	}
	for (int i = 1; i <= 4; i++) {
		if (a[i] >= 90) {
			sum++;
		}
		if (a[i] < 60) {
			cout << "Poor LanYangYang";
			return 0;
		}
	}
	if (sum>=4)
	cout << sum+1;
else
cout<<sum;
	return 0;
}