壹look这题就肥肠简单，用随意用一种排序就出来了：

#include <bits/stdc++.h>
using namespace std;
#define ll long long
char c[4];

void ych(ll &x) {
	int f = 1;
	x = 0;
	char ch = getchar();
	while (ch < '0' || ch > '9') {
		if (ch == '-')
			f = -1;
		ch = getchar();
	}
	while (ch >= '0' && ch <= '9') {
		x = x * 10 + ch - '0';
		ch = getchar();
	}
	x *= f;
}
int main() {
	for (int i = 1; i <= 3; i++) {
		ych(a[i]);
	}
	sort(c + 1, c + 4);
	for (int i = 1; i <= 3; i++) {
		cout << c[3] << c[2] << c[1];
		break;
	}
	return 0;
}
//470