#include <bits/stdc++.h>
using namespace std; int a[25005], b[25005];
int main() { double x, n, a = 1.0; cin >> x >> n; for (int i = 1; i <= n; i++) { a = (a + x / a) / 2; }
cout << fixed << setprecision(3) << a; return 0;
}
Using your 蒙青创OJ universal account